Answer:
The answer is C for first question.
Only D satisfies both of the inequalities in the system represented by the graph. (Please check the graph attached)
Step-by-step explanation:
Lets say that red inequality graph is Graph A, blue inequality graph is Graph B.
First need to find slope of Graph A. Take two points from the graph. (-1,2) and (3,0)
[tex]m= (y_{2}-y_{1})/(x_{2}-x_{1})= (0-2)/(3-(-1)) =-2/4=-1/2[/tex])
Slope of Graph A is -1/2. Lets do it for Graph B. Take two points from Graph B also (-1,2) and (2,0)
[tex]m= (y_{2}-y_{1})/(x_{2}-x_{1})= (0-2)/(2-(-1)) =-2/3[/tex])
Than lets find the in equation with using this slope:
[tex]y-2=(-1/2)*(x-(-1))\\y-2=(-x/2)-1/2\\y=3/2-x/2[/tex]
Below side of the inequality is darked so the inequality A is:
[tex]y<=3/2-x/2[/tex]
Lets find the other inequality:
[tex]y-2=(-2/3)*(x-(-1))\\y-2=(-2x/3)-2/3\\y=(-2x/3)+4/3[/tex]
Upper side of the inequality is darked so the inequality B is:
[tex]y=>(-2x/3)+4/3[/tex]
Correct answer is C