Question

Which is a solution to (X - 3)(x + 9) = -27?

Answer 1

Answer:

$x_{1} =0\\\\x_{2}=-6$

Step-by-step explanation:

We apply distributive property to the polynomial:

(X - 3)(x + 9) = -27

x*x+9*x-3*x-3*9=-27

$x^{2} +9x-3x-27=-27$

$x^{2} +6x-27+27= 0$

$x^{2}+6x+0=0$

we will use the quadratic formula

x=$\frac{-b+-\sqrt{b^{2}-4*a*c}}{2*a}$

a=1    b=6   c=0

we have:

X= $\frac{-6+-\sqrt{6^{2}-4*1*0}}{2*1}$

x= $\frac{-6+-\sqrt{36}}{2}$

X= $\frac{-6+-6}{2}$

so we have

$x_{1} =\frac{-6+6}{2}$

$x_{2} =\frac{-6-6}{2}$

finally we have

$x_{1}$=0

$x_{2}$=-6

Answer 2

Answer:

Answer is C

Step-by-step explanation:

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