Respuesta :

Answer and Explanation:

To find : Perform the indicated operations?

Solution :

Modular math is defined as

[tex]\frac{A}{B}=Q\text{ remainder } R[/tex]

or [tex]A\times Q+R=B[/tex]

Where, A is the dividend

B is the divisor

Q is the quotient

R is the remainder  

The solution is [tex]A mod B = R[/tex]

Now, We perform same in every case

1) [tex](9+6), \mod 5[/tex]

We can direct add the term,

[tex]15 \mod 5[/tex]

Now, we divide 15 by 5 and see the remainder

[tex]5\times 3+0=15[/tex]

Remainder is 0.

So,  [tex]15 \mod 5=0[/tex]

2) [tex](7-11), \mod 12[/tex]

We can direct subtract the term,

[tex]-4 \mod 12[/tex]

Now, we divide -4 by 12 and see the remainder

[tex]12\times (-1)+8=-4[/tex]

Remainder is 8.

So,  [tex]-4 \mod 12=8[/tex]

3) [tex](4\times 3), \mod 5[/tex]

We can direct multiply the term,

[tex]12 \mod 5[/tex]

Now, we divide 12 by 5 and see the remainder

[tex]5\times 2+2=12[/tex]

Remainder is 2.

So, [tex]12 \mod 5=2[/tex]

4) [tex](1\div 2), \mod 5[/tex]

We can direct divide the term,

[tex]0.5 \mod 5[/tex]

Now, we divide 0.5 by 5 and see the remainder

[tex]5\times 0+0.5=0.5[/tex]

Remainder is 0.5.

So,  [tex]0.5 \mod 5=0.5[/tex]

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