Respuesta :

Answer:

62

Step-by-step explanation:

we have given [tex]a> 2[/tex]

then [tex]\frac{2}{a}\ ,\frac{3}{a+1}\ ,\frac{4}{a+2}\ , \frac{5}{a+3}\ ,\frac{6}{a+4}[/tex]

since it is given that [tex]a> 2[/tex]

so [tex]a\equiv 2\ mod\ 4[/tex]  [tex]a\equiv 2\ mod\ 5[/tex]  [tex]a\equiv 2\ mod\ 6[/tex]

[tex]a\equiv2 \left ( mod\ 2,3,4,5,6 \right )[/tex]

[tex]a\equiv2 \left ( mod\ lcm\left ( 2,3,4,5,6 \right )\right )[/tex]

[tex]a\equiv2 \left ( mod\ 60 \right )[/tex]

then a=60n+2 where n is a positive integer

so smallest value of a is a=60×1+2=62

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