Answer:
62
Step-by-step explanation:
we have given [tex]a> 2[/tex]
then [tex]\frac{2}{a}\ ,\frac{3}{a+1}\ ,\frac{4}{a+2}\ , \frac{5}{a+3}\ ,\frac{6}{a+4}[/tex]
since it is given that [tex]a> 2[/tex]
so [tex]a\equiv 2\ mod\ 4[/tex] [tex]a\equiv 2\ mod\ 5[/tex] [tex]a\equiv 2\ mod\ 6[/tex]
[tex]a\equiv2 \left ( mod\ 2,3,4,5,6 \right )[/tex]
[tex]a\equiv2 \left ( mod\ lcm\left ( 2,3,4,5,6 \right )\right )[/tex]
[tex]a\equiv2 \left ( mod\ 60 \right )[/tex]
then a=60n+2 where n is a positive integer
so smallest value of a is a=60×1+2=62