Question

Identify the quadratic function(s). (Select all that apply.)
8-5x = 4(3x - 1)
(48 + 272a-1)+1=0.
1 2y + 2/3y - 5) = 0
2bb-7)+b=0

Answer 1

For this case we have that by definition, a quadratic function is given by:$f (x) =ax ^ 2+ bx + c$

We evaluate the given equations:

Option A:

$8-5x =4(3x-1)\\8-5x=12x-4\\8 + 4 = 12x + 5x$

It is a linear equation!

Option B:

$(48 + 271a-1)+1 = 0\\48 + 271a-1+1 = 0\\48 + 271a = 0$

It is a linear equation!

Option C:

$12y + \frac {2} {3} y-5 = 0\\\frac {36y + 2y} {3} = 5\\36y + 2y = 15$

It is a linear equation!

Option D:

$(2b * b-7) +b = 0\\2b ^ 2-7 + b = 0\\2b ^ 2 + b-7 = 0$

It is a quadratic equation!

ANswer:

Option D