Respuesta :
Answer:
(a - 2) • (3a - 4)
Step-by-step explanation:
(3a2 - 10a) + 8
Trying to factor by splitting the middle term
2.1 Factoring 3a2-10a+8
The first term is, 3a2 its coefficient is 3 .
The middle term is, -10a its coefficient is -10 .
The last term, "the constant", is +8
Multiply the coefficient of the first term by the constant 3 • 8 = 24
Find two factors of 24 whose sum equals the coefficient of the middle term, which is -10 .
-24 + -1 = -25
-12 + -2 = -14
-8 + -3 = -11
-6 + -4 = -10 That's it
Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and -4
3a2 - 6a - 4a - 8
Add up the first 2 terms, pulling out like factors :
3a • (a-2)
Add up the last 2 terms, pulling out common factors :
4 • (a-2)
Add up the four terms of step 4 :
(3a-4) • (a-2)
Which is the desired factorization
Final result :
(a - 2) • (3a - 4)
Answer:
Step-by-step explanation:
3a² - 10a + 8
1. find delta and √delta
∆=(-10)²-4*3*8=100-96=4
√∆=2
2. find a1, a2 with formulas (because ∆>0)
a1= (10+2)/6 = 2
a2=(10-2)/6=4/3
Note: ka²+la+m = k(a-a1)(a-a2)
So answer is 3(a-2)(a-4/3)=(3a-4)(a-2).
OR: we can find a root from factors 8 (it is 2) and then:
3a²-10a+8= 3a² - 6a -4a + 8 = 3a(a-2)-4(a-2)=(3a-4)(a-2)
