Question

A chemistry student needs 15.00g of acetic acid for an experiment. He has available 220.g of a 30.2% w/w solution of acetic acid in benzene. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Be sure your answer has the correct number of significant digits. g ×10No solution

Answer 1

Answer:

4.97 x 10 g

Explanation:

220 g of solution has 30.2% w/w acetic acid.

220 g of the solution has 30.2/100 x 220 g = 66.44 g acetic acid.

15 g of acetic acid is needed.

Hence, if 220 g of solution contains 66.44 g acetic acid, what g will contain 15 g acetic acid?

       220 g solution = 66.44 g acetic acid

        X g solution = 15.00 g acetic acid

              X  = $\frac{220 * 15}{66.44} g$

                   X = 49.6689 g of solution

Therefore, 4.97 x 10 g of the solution should be used by the student.

Answer 2

The study of chemicals is called chemistry. There are two types of solution, one of them is called acidic and the other is called a basic solution.

The correct answer to the question is 4.97 x 10g

What is the solution?

• A solution is defined as the mixture of two different components to form a single liquid.
• These two components are solute and solvent.

SOLUTION

220 g of the solution has 30.2% w/w acetic acid.

220 g of the solution has $\frac{30.2}{100} * 220 g = 66.44$g acetic acid. 15 g of acetic acid is needed.

Hence, if 220 g of solution contains 66.44 g acetic acid, what g will contain 15 g acetic acid?

• 220 g solution = 66.44 g acetic acid
• X g solution = 15.00 g acetic acid

X  = $\frac{220*15}{66.44}$

X = 49.6689 g of solution

Therefore, 4.97 x 10 g of the solution should be used by the student.

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https://brainly.com/question/15209553