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Answer:
Area of the first triangle= B*H/2
Area of the second triangle= B*J
The ratio between the 2 areas of these triangles is 1/2
Step-by-step explanation:
The formula to compute the area of any triangle is =Base * High * (1/2)
The area of the first triangle can be written like this>
[tex]\frac{B*H}{2}[/tex]
Keep in mind that you are instruct to use another triangle that has the same base length of the prior one, but a High twice, so the area of the second triangle can be written like this>
[tex]\frac{B*(2*H)}{2}[/tex]
The ratio between them is no more than a propotion, that is the following operation>
[tex]\frac{A1}{A2}[/tex]
Which, you can substitute by your expressions:
[tex]\frac{B*H}{2} / \frac{B*H}{1}[/tex]
Giving you the following:
[tex]\frac{B*H}{2*B*H}[/tex]
Here, just simplify all terms that are equals and boom, there you have it