SUPER EASY WILL GIVE BRAINLEIST IF DONE BEFORE 10 P.M. PLS HURRY. IF U HAVE TIME PLS HELP ME ON OTHER QUESTIONS THANK YOU

SUPER EASY WILL GIVE BRAINLEIST IF DONE BEFORE 10 PM PLS HURRY IF U HAVE TIME PLS HELP ME ON OTHER QUESTIONS THANK YOU class=

Respuesta :

Answer:

Area of the first triangle= B*H/2

Area of the second triangle= B*J

The ratio between the 2 areas of these triangles is 1/2

Step-by-step explanation:

The formula to compute the area of any triangle is =Base * High * (1/2)

The area of the first triangle can be written like this>

[tex]\frac{B*H}{2}[/tex]

Keep in mind that you are instruct to use another triangle that has the same base length of the prior one, but a High twice, so the area of the second triangle can be written like this>

[tex]\frac{B*(2*H)}{2}[/tex]

The ratio between them is no more than a propotion, that is the following operation>

[tex]\frac{A1}{A2}[/tex]

Which, you can substitute by your expressions:

[tex]\frac{B*H}{2} / \frac{B*H}{1}[/tex]

Giving you the following:

[tex]\frac{B*H}{2*B*H}[/tex]

Here, just simplify all terms that are equals and boom, there you have it

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