Question

Calculate the number of moles in the 2.1-L volume of air in the lungs of the average person. Note that the air is at 37.0ºC (body temperature). Use standard atmospheric pressure.

Answer 1

Answer: 0.0826mol

PV=nRT
n=PV/RT
n=(1atm)(2.1L)/(310K)(0.082057L*atm/mol*K)=0.0826mol