Question

what is the value of x?

Answer 1

$x^2=40^2+9^2\\x^2=1600+81\\x^2=1681\\x=\sqrt{1681}=41$

Answer 2

To solve this you must use Pythagorean theorem:

$a^{2} +b^{2} =c^{2}$

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 9

b = 40

c = x

^^^Plug these numbers into the theorem

$9^{2} +40^{2} =x^{2}$

simplify

81 + 1600 = $x^{2}$

1681 = $x^{2}$

To remove the square from x take the square root of both sides to get you...

41 = x  

Hope this helped!

~Just a girl in love with Shawn Mendes