Question

Scott had an average of 83 on his first three exams. He later scored an average of 92 on the next six exams. What is his average for all nine exams. Round to the nearest tenth if necessary.

Answer 1

Answer:89

Step-by-step explanation:

Given scott had an average of 83 on his first three exams

i.e. the sum of first three exams $\sum S_1=83\times 3$

later he scored an average on the next six exams

i.e. the sum of later 6 exams is $\sum S_2=92\times 6$

$\sum S_1+\sum S_2=83\times 3+92\times 6=801$

therefore his average score is =$\frac{801}{9}=89$

Thus his average score is 89