Question

A 12000 kg boat is moving 4.25 m/s. Its engine pushes 9200 N forward, but the current pushes back at 12,500 N. How much times does it take the boat to stop?

Answer 1

Answer:

15.5 seconds

Explanation:

Apply Newton's second law:

∑F = ma

-12500 + 9200 = (12000) a

a = -0.275 m/s²

v = at + v₀

0 = (-0.275) t + 4.25

t = 15.5 s

It takes the boat 15.5 seconds to stop.

Answer 2

Time  = 15.74 sec

What is newton's second law?

The newton's second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object

v = u + at

v =0

u = 4.25 m/s

a = ?

to find = time (t)= ?

from newton's third law

∑ F = mass * acceleration

-12500 + 9200 = 12000 * a

- 3300 = 12000 a

a = - 0.275 m/$s^{2}$

since , v = u + at

0 = 4.25  + ( - 0.275 * time)

Time =  4.25 / 0.27

Time  = 15.74 sec

learn more about newton's third law

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