Which additional congruence statement could you use to prove that RQS= PQS by hl

Answer:
The correct answer is last option SR ≅ SP
Step-by-step explanation:
Points to remember
IF two right angled triangles are congruent by HL congruence, then one leg and hypotenuse of both are congruent,
To find the correct option
From the figure we get,
SQ is the common side of two triangles.
SR is the hypotenuse of ΔRQS and
SP is the hypotenuse of ΔPQS
Therefore we need SR ≅ SP
The correct answer is last option SR ≅ SP