Answer:
15 times the first equation and -12 times the second equation
Step-by-step explanation:
we have
[tex]\frac{3}{4}x+\frac{2}{3}y=6[/tex] ------> first equation
[tex]\frac{5}{8}x+\frac{5}{6}y=12[/tex] ------> second equation
Multiply the first equation by 15 both sides
[tex](15)\frac{3}{4}x+(15)\frac{2}{3}y=6(15)[/tex]
[tex]\frac{45}{4}x+10y=90[/tex] -----> new first equation
Multiply the second equation by -12 both sides
[tex](-12)\frac{5}{8}x+(-12)\frac{5}{6}y=12(-12)[/tex]
[tex]-\frac{60}{8}x-10y=-144[/tex] -----> new second equation
Adds the two new equations
[tex]\frac{45}{4}x+10y=90\\-\frac{60}{8}x-10y=-144\\-----------\\\frac{45}{4}x-\frac{60}{8}x=90-144[/tex]
The y-term was eliminated
