helpp please!!!
Arrange the functions according to the positions of their horizontal asymptotes on the coordinate plane, starting with the lowest and ending with the highest.

helpp please Arrange the functions according to the positions of their horizontal asymptotes on the coordinate plane starting with the lowest and ending with th class=

Respuesta :

Answer:

  h, j2, f, g, j1, i, k, l (ell)

Step-by-step explanation:

The horizontal asymptote is the constant term of the quotient of the numerator and denominator functions. Generally, it it is the coefficient of the ratio of the highest-degree terms (when they have the same degree). It is zero if the denominator has a higher degree (as for function f(x)).

We note there are two functions named j(x). The one appearing second from the top of the list we'll call j1(x); the one third from the bottom we'll call j2(x).

The horizontal asymptotes are ...

  • h(x): 16x/(-4x) = -4
  • j1(x): 2x^2/x^2 = 2
  • i(x): 3x/x = 3
  • l(x): 15x/(2x) = 7.5
  • g(x): x^2/x^2 = 1
  • j2(x): 3x^2/-x^2 = -3
  • f(x): 0x^2/(12x^2) = 0
  • k(x): 5x^2/x^2 = 5

So, the ordering least-to-greatest is ...

  h (-4), j2 (-3), f (0), g (1), j1 (2), i (3), k (5), l (7.5)

Answer:

The photo is blurry but it shows the answer is CORRECT. The correct sequence is,

h

j(x)=3x^2-x+1 / 1-x^2

f

g

j(x)=2x^2-3x+17 / (x-5)^2

i

k

l

Step-by-step explanation:

In case you found the above answer confusing, here is this !! Hope I could help :)

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