Question

#14-8: A sack contains only purple, green, and yellow beads. If selected at random, the P(purple)= 1/5 and P(green)= 1/10. What is the probability of selecting a yellow bead? Express the probability as a number between 0 and 1.

Answer 1

Answer:

0.7

Step-by-step explanation:

The way to solve this is to subtract the two fractions from 1.

P(y) = 1 - (1/5 + 1/10)

P(y) = 1 - (2/10 + 1/10)

P(y) = 1 - (3/10)

P(y) = 7/10

7/10 = 0.7

Answer 2

Answer:

P(yellow) = $\frac{7}{10}$

Step-by-step explanation:

A sack contains: Purple, Green and Yellow beads

If selected at random;

P(purple) = $\frac{1}{5}$

P(green) =  $\frac{1}{10}$

P(yellow) = x

P(purple) + P(green) + P(yellow) = 1

i.e  $\frac{1}{5}$ +  $\frac{1}{10}$ + x = 1

x = 1 - ( $\frac{1}{5}$ +  $\frac{1}{10}$) =  $\frac{7}{10}$