The percentage of given probability is 69%. Using the Z-table the value is calculated.
The standard normal distribution tells about the distribution whose mean is zero and the standard deviation is 1. This is also called z-distribution. The z-score is calculated by z = (x - μ)/ σ.
The given probability is P(z < 0.5)
From the z-table,
we have P(z < 0.5) = 0.6915
So, converting it into percentage we get 69%.
∴ P(X < 13) = P(z < 0.5) = 69%
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