Respuesta :
The elements present in Ammonium Nitrate are Hydrogen, Nitrogen, and Oxygen at a ratio of 4:2:3, respectively. Hydrogen weighs in at 1.008 amu, Nitrogen at 14.007, and Oxygen at 15.999. This means that the molar mass would be:
Hydrogen
4 x 1.008 = 4.032 amu
Nitrogen
2 x 14.007 = 28.014 amu
Oxygen
3 x 15.999 = 47.997 amu
Total
4.032 + 28.014 + 47.997 = 80.043 amu
The molar mass of Ammonium Nitrate is 80.043 grams per mole.
Hydrogen
4 x 1.008 = 4.032 amu
Nitrogen
2 x 14.007 = 28.014 amu
Oxygen
3 x 15.999 = 47.997 amu
Total
4.032 + 28.014 + 47.997 = 80.043 amu
The molar mass of Ammonium Nitrate is 80.043 grams per mole.
Answer:
D (nitrogen, hydrogen, and oxygen)
For the second question it's 2, 4, 3 (IN ORDER)
The last questions answer is 80.0
Explanation:
For edge:)
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