Question

Calculate the percent by mass of each element in
ammonium nitrate (NH4NO3).
The first step is to calculate the molar mass of
ammonium nitrate.
What elements are present in ammonium nitrate?

Answer 1

Answer:

See below in bold.

Explanation:

Nitrogen, Hydrogen and Oxygen are the elements present in ammonium nitrate.

The Molar Mass =  2N + 4H  + 3 O

= 2*14.007 + 4*1.008 + 3*15.999

= 80.043.

Percentage of Nitrogen = (2 * 14.007) * 100 / 80.043

= 35.00 %.

Percentage of Hydrogen = (4* 1.008) * 100 / 80.043

= 5.04%.

Percentage of Oxygen = (3 * 15.999) * 100 / 80.043

= 59.96 %.

Answer 2

Ammonium nitrate ($NH_4NO_3$) is a white crystalline chemical compound which is highly soluble is water.

Molar mass of Ammonium nitrate ($NH_4NO_3$)

First we have to calculate the molar mass of ammonium nitrate

Molar mass of one mol of $NH_4NO_3$ =  80.043g

Percent by mass of each element in Ammonium nitrate($NH_4NO_3$)

Now we are calculating percentage mass of each element in $NH_4NO_3$

Percentage mass of nitrogen:

$2 \times 14.0007g = 28.0014$

Mass of nitrogen = 28.0014g

Percent composition of Nitrogen is

$\rm{\%\;of\;N=\frac{28.0014}{80.043} \times 100 = 35.00 \%$

Percentage of N = 35.00 %

Percentage mass of hydrogen:

$4 \times 1.008 = 4.032$

Mass of hydrogen = 4.032g

Percent composition of hydrogen is

$\rm{\%\;of \;H=\frac{4.032}{80.043} \times 100 = 5.04\%$

Percentage of H = 5.04%

Percentage mass of oxygen:

$3 \times 15.999 = 47.997$

Mass of oxygen = 47.997g

Percent composition of oxygen is

$\rm{\%\; of\; O}=\frac{47.997}{80.043} \times 100 = 59.96\%$

Percentage of O = 59.96%

The elements present in ammonium nitrate are:

Nitrogen (N), Oxygen (O), Hydrogen (H).

Hence, To calculate the percent by mass of each element in ammonium nitrate, first we have to calculate the molar mass of ammonium nitrate and then multiply the molar mass of ammonium nitrate by the mass of each element and divide by hundred.

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