Answer:
[tex]\large\boxed{x-intercept=16\to(16,\ 0)}\\\boxed{y-intercept=\dfrac{9}{4}\to\left(0,\ \dfrac{9}{4}\right)}[/tex]
Step-by-step explanation:
[tex]\dfrac{9}{8}x+8y=18\\\\x-intercept\ \text{is for}\ y=0:\\\\\dfrac{9}{8}x+8(0)=18\\\\\dfrac{9}{8}x+0=18\\\\\dfrac{9}{8}x=18\qquad\text{multiply both sides by}\ \dfrac{8}{9}\\\\\dfrac{8\!\!\!\!\diagup^1}{9\!\!\!\!\diagup_1}\cdot\dfrac{9\!\!\!\!\diagup^1}{8\!\!\!\!\diagup_1}x=\dfrac{8}{9\!\!\!\!\diagup_1}\cdot18\!\!\!\!\!\diagup^2\\\\x=16\\\\y-intercept\ \text{is for}\ x=0:\\\\\dfrac{9}{8}(0)+8y=18\\\\0+8y=18\\\\8y=18\qquad\text{divide both sides by 8}\\\\y=\dfrac{18}{8}\\\\y=\dfrac{9}{4}[/tex]
Answer:
(16, 0) and (0, [tex]\frac{9}{4}[/tex])
Step-by-step explanation:
Given
[tex]\frac{9}{8}[/tex] x + 8y = 18
Multiply through by 8 to eliminate the fraction
9x + 64y = 144
When the graph crosses the x- axis the y- coordinate of the point is zero.
Let y = 0 in the equation and solve for x
9x +0 = 144
9x = 144 ( divide both sides by 9 )
x = 16 ← x - intercept ⇒ (16, 0 )
When the graph crosses the y- axis the x- coordinate of the point is zero
let x = 0 in the equation and solve for y
0 + 64y = 144
64y = 144 ( divide both sides by 64 )
y = [tex]\frac{144}{64}[/tex] = [tex]\frac{9}{4}[/tex] ← y- intercept ⇒ (0, [tex]\frac{9}{4}[/tex] )
