Find the equation for the linear function that passes through the points (−5,−6) and (10,0). Answers must use whole numbers and/or fractions, not decimals.

Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 5, - 6) and (x₂, y₂ ) = (10, 0)
m = [tex]\frac{0+6}{10+5}[/tex] = [tex]\frac{6}{15}[/tex] = [tex]\frac{2}{5}[/tex], hence
y = [tex]\frac{2}{5}[/tex] x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (10, 0), then
0 = 4 + c ⇒ c = 0 - 4 = - 4
y = [tex]\frac{2}{5}[/tex] x - 4 ← equation of line