In a certain cyclotron a proton moves in a circle of radius 0.670 m. The magnitude of the magnetic field is 1.30 T. (a) What is the oscillator frequency? (b) What is the kinetic energy of the proton?

Respuesta :

a) The formula for a cyclotron's frequency:

f = (qB)/(2πm)

f is the frequency, q is the particle's charge, B is the magnetic field strength, and m is the particle's mass.

Given values:

q = 1.6×10⁻¹⁹C (proton charge)

B = 1.30T

m = 1.67×10⁻²⁷kg (proton mass)

Plug in these values and solve for f:

f = (1.6×10⁻¹⁹×1.30)/(2π×1.67×10⁻²⁷)

f = 1.98×10⁷Hz

b) The kinetic energy of a particle in the cyclotron is:

KE = 0.5q²B²r²/m

q is the particle's charge, B is the magnetic field strength, r is the radius of the particle's path, and m is the particle's mass.

Given values:

q = 1.6×10⁻¹⁹C (proton charge)

B = 1.30T

r = 0.670m

m = 1.67×10⁻²⁷kg (proton mass)

Plug in the values and solve for KE:

KE = (0.5)(1.6×10⁻¹⁹)²(1.30)²(0.670)²/1.67×10⁻²⁷

KE = 5.81×10⁻¹²J

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