Question

Part A If a sample of gold having a mass of 27.63 g is pressed into a thing foil of 1,000 mierometer thickness, then what is the area of the foi? The density of gold is 19.32 g/cm3

Answer 1

Answer:

The area of the gold foil is $14.3 cm^{2}$

Explanation:

Mass of gold foil , m= 27.63 g

Thickness of gold foil , $t=1000\mu m=0.1 cm$

Density of gold , $\rho =19.32\frac{g}{cm^{3}}$

Let the area of gold foil be A then the total volume of gold foil is given by

$V=At=\frac{m}{\rho }$

=>$A=\frac{m}{t\rho }=\frac{27.63}{0.1\times 19.32} cm^{2}$

=>$A=14.3 cm^{2}$

Thus the area of the gold foil is $14.3 cm^{2}$