Explanation:
1. The kinetic energy of any object is calculated as :
[tex]E=\dfrac{1}{2}mv^2[/tex]...........(1)
Dimensional formula of energy, [tex][E]=[ML^2T^{-2}][/tex]
Dimensional formula of mass is [tex][M][/tex]
Dimensional formula of velocity, [tex][v]=[LT^{-1}][/tex]
[tex][ML^2T^{-2}]=\dfrac{1}{2}[M]([LT^{-1}])^2[/tex]
So, [tex][ML^2T^{-2}]=[ML^2T^{-2}][/tex]
LHS = RHS
2. The potential energy is given by :
[tex]E=mgh[/tex]
Dimensional formula of mass is [tex][M][/tex]
Dimensional formula of g is [tex][LT^{-2}][/tex]
Dimensional formula of height is [tex][L][/tex]
Dimensional formula of energy, [tex][E]=[ML^2T^{-2}][/tex]
So, [tex]E=[M][LT^{-2}][L][/tex]
So, LHS = RHS
Hence, this is the required solution.