Answer:
[tex]\dfrac{4}{x}=\dfrac{1}{x-16}[/tex]
[tex]21\dfrac{1}{3}\ \text{minutes}[/tex]
Step-by-step explanation:
Let x be the number of minutes the flight was expected to take. Actually, the flight will take (x+16) minutes.
Let S be the distance to be covered.
Expected speed [tex]=\dfrac{S}{x}[/tex]
Actual speed [tex]=\dfrac{S}{x-16}[/tex] (shee will be flying 16 minutes less)
The pilot will be able to travel four times faster than expected if she waits, so
[tex]4\cdot \dfrac{S}{x}=\dfrac{S}{x-16}\ \ \ \text{[Divide by S]}\\ \\\dfrac{4}{x}=\dfrac{1}{x-16}\ \ \ \text{[Cross multiply]}\\ \\4(x-16)=x\\ \\4x-64=x\\ \\4x-x=64\\ \\3x=64\\ \\x=\dfrac{64}{3}=21\dfrac{1}{3}\ \text{minutes}[/tex]