As outlaws escape in their getaway ear, which goes 3/4 c, the police officer fires a bullet from a pursuit ear, which only goes 1/2 c. The muzzle velocity of the bullet (relative to the gun) is 1/3 c. Does the bullet reach its target according to Galileo according to Einstein?

Respuesta :

Answer:

a) Bullet will hit

b) Bullets will not hit

Explanation:

Given:

The velocity of the bullet, u = [tex]\frac{1}{3}c[/tex] in the rest frame of the bullet pursuit car

The velocity of the original frame of reference, v = [tex]-\frac{1}{2}c[/tex] with respect to the pursuit car.

Now, according to the Galileo

the velocity of the bullet in the original frame of reference (u') will be

u' = u - v

on substituting the values we get

u' = [tex]\frac{1}{3}c-(-\frac{1}{2}c)[/tex]

or

u' = [tex]\frac{1}{3}c+\frac{1}{2}c[/tex]

or

u' = [tex]\frac{5}{6}c[/tex]

since this velocity ( [tex]\frac{5}{6}c[/tex]) is greater than the ( [tex]\frac{3}{4}c[/tex])

hence,

the bullet will hit

Now, according to the Einstein theory

the velocity of the bullet in the original frame of reference (u') will be

[tex]u'=\frac{u-v}{1-\frac{uv}{c^2}}[/tex]

on substituting the values we get

[tex]u'=\frac{\frac{1}{3}c-\frac{1}{2}c}{1-\frac{\frac{1}{3}c\times \frac{1}{2}c}{c^2}}[/tex]

or

[tex]u'=\frac{\frac{5}{6}c}{1-\frac{1}{6}}[/tex]

or

[tex]u'=\frac{5}{7}c[/tex]

since,

[tex]u'=\frac{5}{7}c[/tex] is less than  ( [tex]\frac{3}{4}c[/tex]), this means that the bullet will not hit

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