Answer:
The least amount of time in which the fisherman can raise the fish to the dock without losing it is t= 2 seconds.
Explanation:
m= 5 kg
h= 2m
Fmax= 54 N
g= 9.8 m/s²
W= m * g
W= 49 N
F= Fmax - W
F= 5 N
F=m*a
a= F/m
a= 1 m/s²
h= a * t²/2
t= √(2*h/a)
t= 2 seconds