Answer:
[tex]x^2+y^2=25[/tex]
Step-by-step explanation:
Recall the following Pythagorean Identity:
[tex]\sin^2(\theta)+\cos^2(\theta)=1[/tex]
Let's solve the x equation for cos(t) and the y equation for sin(t).
After the solve we will plug into our above identity.
x=5cos(t)
Divide both sides by 5:
(x/5)=cos(t)
y=5sin(t)
Divide both sides by 5:
(y/5)=sin(t)
Now we are ready to plug into the identity:
[tex]\sin^2(t)+\cos^2(t)=1[/tex]
[tex](\frac{y}{5})^2+(\frac{x}{5})^2=1[/tex]
[tex]\frac{x^2}{5^2}+\frac{y^2}{5^2}=1[/tex]
Multiply both sides by 5^2:
[tex]x^2+y^2=5^2[/tex]
This is a circle with center (0,0) and radius 5.
All I did to get that was compare our rectangular equation we found to
[tex](x-h)^2+(y-k)^2=r^2[/tex]
where (h,k) is the center and r is the radius of a circle.