Respuesta :

Answer:

-1/3 is the slope perpendicular

Step-by-step explanation:

When we have 2 points, we can use the formula

m = (y2-y1)/(x2-x1) to find the slope

m = (1-7)/(3-5)

   =-6/-2

    =3

The slope is 3

We want a slope perpendicular

Remember that is the negative reciprocal

- (1/3)

-1/3

r3t40

Two lines are perpendicular when,

[tex]a_1=-a_2^{-1}[/tex]

Now solve for [tex]a_2[/tex] to get [tex]a_2=-a_1^{-1}[/tex]

First we calculate the slope [tex]a_1[/tex] from the given points [tex]E(x_1,y_1),F(x_2,y_2)\longrightarrow E(5,7),F(3,1)[/tex].

[tex]a_1=\dfrac{\Delta{y}}{\Delta{x}}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1-7}{3-5}=\dfrac{-6}{-2}=3[/tex]

Now use the first formula and insert the data in it to find the value of the second slope [tex]a_2[/tex],

[tex]a_2=-3^{-1}=\boxed{-\dfrac{1}{3}}[/tex]

And that's it.

Hope this helps.

r3t40

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