Answer:
299.36 kPa
Explanation:
given mass of steam =2 kg
initial pressure that is [tex]P_1=500kPa[/tex]
initial temperature that is [tex]T_1=350^{\circ} C=350+273=623 K[/tex]
final temperature that is [tex]T_2=100^{\circ} C=100+273=373 K[/tex]
it is a rigid tank so volume is constant
for constant volume process [tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
[tex]P_2=\frac{T_2}{T_1}\times P_1=\frac{373}{623}\times 500=299.36 kPa[/tex]
so the final pressure will be 299.36 kPa