Given:
parasite Drag Coefficient,[tex]C _{D}[/tex] is reduced by 19% or 0.19 times
Solution:
Using Breguet's Endurance Eqn:
[tex]E = t_{2} - t_{1} = - \int_{W_{1}}^{W_{2}}\frac{dW}{c_{t}D}[/tex]
or
[tex]E = \frac{1}{c_{t}}\frac{C_{L}}{C_{D}}\ln\frac{W_{1}}{W_{2}}[/tex] (1)
From eqn (1), other terms being constant, then
[tex]E = K\frac{1}{C_{D}}[/tex]
or
[tex]E\propto\frac{1}{C_D}[/tex]
Therefore, the above relation shows that when drag coefficient [tex]C _{D}[/tex] decreases performance increases and vice-versa due to inverse relation between the.
So, 19% decrease will result in:
[tex]E = \frac{1}{0.19}[/tex] = 5.26 times increase in performance