Consider an open loop 1-degree-of-freedom mass-spring damper system. The system has mass 4.2 kg, and spring stiffness of 85.9 N/m, and damping coefficient of 1.3 N.s/m. What is the non-dimensional damping ratio of the system? Use at least 4 significant digits after the decimal point.

Respuesta :

Answer:

Damping ratio  [tex]\zeta =0.0342[/tex]

Explanation:

Given that

m=4.2 kg,K=85.9 N/m,C=1.3 N.s/m

We need to find damping ratio

We know that critical damping co-efficient

 [tex]C_c=2\sqrt {mk}[/tex]

 [tex]C_c=2\sqrt {4.2\times 85.9}[/tex]

 [tex]C_c=37.98[/tex] N.s/m

Damping ratio([tex]\zeta[/tex]) is the ratio of damping co-efficient to the critical damping co-efficient

So [tex]\zeta =\dfrac{C}{C_c}[/tex]

[tex]\zeta =\dfrac{1.3}{37.98}[/tex]

[tex]\zeta =0.0342[/tex]

So damping ratio  [tex]\zeta =0.0342[/tex]

 

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