Question

Calculate the mass of sodium acetate trihydrate required to make 100. mL of a 0.100 M solution. 0.820 g 1.00 g 1.36 g 1.95 g

Answer 1

Answer:

1.36 g.

Explanation:

First we calculate the molar mass of sodium acetate trihydtrate:

CH3COONa.3H2O

= 12 + 3 + 12 + 2*16 + 23 + 6 + 3*16

=  136 g.

So 1 L of  1 M solution  contains 136 g

0.100 M solution will contain 13.6 g

100 mL of 0.100 M solution contains 1.36 g.