Question

Which explains whether Kadesha is correct?

Kadesha is correct because triangle ABC is the pre-image and triangle A'B'C' is the image.

Kadesha is correct because each point in triangle ABC moves five units up.

Kadesha is not correct because the number of units between points A and B is different than those between points A' and B'.

Kadesha is not correct because a translation is a horizontal movement

Answer 1

I believe the answer is the third one

Answer 2

Answer with explanation:

 Coordinates of vertices of ΔABC are =A(1,-1), B(1,-4),C(4,-4)

  Coordinates of vertices of ΔA'B'C' are =A'(1,5), B'(1,1),C(4,1)

Suppose, Preimage =ΔABC

Image =ΔA'B'C'

If you will find distance between two vertices of Both the triangles or length of sides of triangles

$AB=3\\\\BC=3\\\\AC=\sqrt{(4-1)^2+(-4+1)^2}\\\\AC=\sqrt{18}\\\\AC=3\sqrt{2}\\\\A'B'=4\\\\B'C'=3\\\\A'C'=\sqrt{(4-1)^2+(1-5)^2}\\\\A'C'=\sqrt{9+16}\\\\A'C'=5$

Option C is most Appropriate.

Kadesha is not correct because the number of units between points A and B is different than those between points A' and B'.