Graph the line with slope -1/3 and y-intercept-3.

Answer:
The graph in the attached figure
Step-by-step explanation:
we know that
The equation of the line into slope intercept form is equal to
[tex]y=mx+b[/tex]
where
m is the slope
b is the y-intercept
In this problem we have
[tex]m=-\frac{1}{3}[/tex]
[tex]b=-3[/tex]
substitute
[tex]y=-\frac{1}{3}x-3[/tex]
To graph the line find out the intercepts
Find the y-intercept
The y-intercept is the value of y when the value of x is equal to zero
so
For x=0
[tex]y=-\frac{1}{3}(0)-3=-3[/tex]
The y-intercept is the point (0,-3) -----> is a given value
Find the x-intercept
The x-intercept is the value of x when the value of y is equal to zero
so
For y=0
[tex]0=-\frac{1}{3}x-3[/tex]
[tex]x=-9[/tex]
The x-intercept is the point (-9,0)
Plot the intercepts and join the points to graph the line
see the attached figure