Respuesta :
Answer:
We have ; p = 2050
r = [tex]12/12/100=0.01[/tex]
n = [tex]3\times12=36[/tex]
But we will take [tex]36-5=31[/tex]
EMI formula is :
[tex]\frac{p\times r\times(1+r)^{n}}{(1+r)^{n}-1}[/tex]
Substituting values in the formula we get;
[tex]\frac{2050\times0.01\times(1+0.01)^{31}}{(1+0.01)^{31}-1}[/tex]
= [tex]\frac{2050\times0.01\times(1.01)^{31}}{(1.01)^{31}-1}[/tex]
= $77.24
Now for further working you can see the sheet attached.
Total interest paid for the loan = $446.76