Respuesta :
Answer:
The c++ program is shown below.
#include <iostream>
using namespace std;
int main() {
cout<<"Numbers less than 1000 which are divisible by 7"<<endl;
for(int k=1; k<1000; k++)
{
// number should give remainder 0 which show complete divisibility
if(k%7 == 0)
cout<<k<<"\t";
}
cout<<endl<<"Numbers less than 1000 which are divisible by 11"<<endl;
for(int k=1; k<1000; k++)
{
if(k%11 == 0)
cout<<k<<"\t";
}
cout<<endl<<"Numbers less than 1000 which are divisible by 7 but not divisible by 11"<<endl;
for(int k=1; k<1000; k++)
{
// for 11, number should not give remainder 0 which shows incomplete divisibility
if(k%7 == 0 && k%11 != 0)
cout<<k<<"\t";
}
cout<<endl<<"Numbers less than 1000 which are divisible by 7 and divisible by 11"<<endl;
for(int k=1; k<1000; k++)
{
if(k%7 == 0 && k%11 == 0)
cout<<k<<"\t";
}
cout<<endl<<"Numbers less than 1000 which are not divisible by 7 and not divisible by 11"<<endl;
for(int k=1; k<1000; k++)
{
if(k%7 != 0 && k%11 != 0)
cout<<k<<"\t";
}
return 0;
}
Explanation:
The test for divisibility is done by using the modulus operator which is used as a condition inside the if statement. This test is done inside for loop.
All the numbers from 1 to 999, less than 1000, are divided by 7 and/ or 11 depending on the sub question. Only the numbers which are completely divisible are displayed. Divisible numbers give remainder 0 always.
The divisibility test by 7 is shown below.
cout<<"Numbers less than 1000 divisible by 7"<<endl;
for(int k=1; k<1000; k++)
{
if(k%7 == 0)
cout<<k<<"\t";
}
In other words, all the numbers divisible by 7 are same as the numbers in the table of 7.
The same logic shown above is applied for other sub questions to test for divisibility by 11 and combination of 7 and 11.
To improve readability, tabs and new lines are inserted at appropriate places.
