Answer:
minimum (3,7)
Step-by-step explanation:
y = x^2 - 6x + 16
Take the coefficient of the x term -6
Divide it by 2 -6/2 =-3
Then square it ( -3)^2 =9
Add that to the equation (remember if we add it we must subtract it)
y = x^2 - 6x +9 -9+ 16
y = (x^2 - 6x +9) -9+ 16
The term inside the parentheses is x+b/2 which is x+ -3 or x-3 quantity squared
y = (x-3)^2 +7
This is in vertex form
y = a(x-h)^2 +k where (h,k) is the vertex
(3,7) is the vertex
Since a=1, it is positive, so it opens upward and the vertex is a minimum
