Answer:
[tex]d = 10\times t\sqrt{29}miles[/tex]
Explanation:
Given:
't' hour be the time taken for travel by both the vehicles and 'd' be the distance between then
then
Distance traveled by the car = 20 × t miles
and
Distance traveled by the truck = 50 × t miles
now, using the Pythagoras theorem
[tex]d = \sqrt{(20t)^2+(50t)^2}[/tex]
or
[tex]d = \sqrt{400t^2+2500t^2}[/tex]
or
[tex]d = \sqrt{2900t^2}[/tex]
or
[tex]d = 10\times t\sqrt{29}[/tex]
thus, the equation relating the distance 'd' with the time 't' comes as
[tex]d = 10\times t\sqrt{29}miles[/tex]