Answer:
First exercise: [tex]x=7[/tex]
Second exercise: [tex]x=2[/tex]
Step-by-step explanation:
Acording to the Intersecting Secants Theorem the products of the segments of two secants that intersect each other outside a circle, are equal.
Based on this, in order to solve the first exercise and the second exercise, we can write the following expressions and solve for "x":
First exercise:
[tex](5)(5+x)=6(6+4)\\\\25+5x=60\\\\5x=60-25\\\\x=\frac{35}{5}\\\\x=7[/tex]
Second exercise:
[tex](4)(4+x)=3(3+5)\\\\16+4x=24\\\\4x=24-16\\\\x=\frac{8}{4}\\\\x=2[/tex]
