Answer: The probability that both televisions work : 0.5329
The probability at least one of the two televisions does not work : 0.4671
Step-by-step explanation:
Given : The total number of television : 11
The number of defective television : 3
The probability that the television is defective : [tex]p=\dfrac{3}{11}\approx0.27[/tex]
Binomial distribution formula :-
[tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex], where P(X) is the probability of getting success in x trials, p is the probability of success and n is the total trials.
If two televisions are randomly selected, then the probability that both televisions work:
[tex]P(0)=^2C_0(0.27)^0(1-0.27)^{2-0}=(1)(0.73)^2=0.5329[/tex]
The probability at least one of the two televisions does not work :
[tex]P(X\geq1)=1-P(0)=1-0.5329=0.4671[/tex]
