Respuesta :

Answer with Step-by-step explanation:

Since we have given that

[tex]BA=I[/tex]

As we know that

AA⁻¹ = I (A is invertible matrix)

Multiplying A⁻¹ on the both the sides:

[tex]BAA^{-1}=IA^{-1}\\\\B=A^{-1}[/tex]

Using the above result, we get that

[tex]BA=I=AA^{-1}\\\\BA=AB[/tex]

Therefore, BA = AB

Hence, proved.

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