Answer:
Genotype of the father: Heterozygous dominant (Aa)
Explanation:
Let's suppose allele "a" is responsible for albinism while allele "A" gives normal phenotype.
Given that Albinism is a recessive trait, it will be expressed in a homozygous recessive genotype only. The female snake is albino and hence, her genotype is= "aa".
Since the progeny have both normal and albino snake, the male parent should be heterozygous dominant (Aa) with one copy of normal allele and one copy of recessive allele.