Answer:
The light takes 4.73×10⁻²³ s to travel across the width of the Pb nucleus.
Explanation:
Given :
Radius of Pb nucleus = 7.1 fm
Also, The conversion of fm into m is shown below:
1 fm = 10⁻¹⁵ m
The radius of Pb nucleus = 7.1×10⁻¹⁵ m
The width of Pb nucleus (diameter) = 2× Radius of the nucleus
Thus,
Width of Pb nucleus = 2×7.1×10⁻¹⁵ m = 14.2×10⁻¹⁵ m
The Speed of light = 3×10⁸ m/s
The formula for Speed is shown below:
[tex]Speed=\frac{Distance}{Time}[/tex]
Time can be calculated from the above formula as:
[tex]Time=\frac{Distance}{Speed}[/tex]
Applying values in the above formula as:
[tex]Time=\frac{14.2\times 10^{-15} m}{3\times 10^{8} m/s}[/tex]
Time = 4.73×10⁻²³ s
