Answer: Probability that she attended class regularly given that she receives A grade is 0.9286.
Step-by-step explanation:
Since we have given that
Probability of those who attend regularly receive A's in the class = 35%
Probability of those who do not regularly receive A's in the class = 5%
Probability of students who attend class regularly = 65%
We need to find the probability that she attended class regularly given that she receives an A grade.
Let E be the event of students who attend regularly.
P(E) = 0.65
And P(E') = 1-0.65 = 0.35
Let A be the event who attend receive A in the class.
So, P(A|E) = 0.35
P(A|E') = 0.05
So, According to question, we have given that
[tex]P(E|A)=\dfrac{P(E)P(A|E)}{P(E)P(A|E)+P(E')P(A|E')}\\\\P(E|A)=\dfrac{0.65\times 0.35}{0.65\times 0.35+0.35\times 0.05}\\\\P(E|A)=\dfrac{0.2275}{0.2275+0.0175}=\dfrac{0.2275}{0.245}=0.9286[/tex]
Hence, Probability that she attended class regularly given that she receives A grade is 0.9286.