An hydraulic cylinder has a piston diameter of 150mm and strokes at 300mm in 10 seconds. Calculate- A) The swept volume of the actuator in liters B) The pump displacement in Liters/minute

Respuesta :

Answer:

(a)Volume in liters=5.3 liters.

(b)Volume in liters/minute=31.8 liters/minute.

Explanation:

Given:  

   Diameter of cylinder ,D=150 mm

                         Stroke,L=300 mm

                         Time ,t=10 sec

we know that swept volume of cylinder

          [tex]V_{s}=\dfrac{\pi }{4}\times D^2\times L[/tex]

So [tex]V_{s}=\dfrac{\pi }{4}\times 0.15^2\times 0.3 m^{3}[/tex]

     [tex]V_{s}=0.0053 m^3[/tex]

(a) Volume in liters =5.3 liters         ( 1[tex]m^3[/tex]=1000 liters)

(b) When we divide swept volume  by time(in minute) we will get liters/minute.

 We know that 1 minute=60 sec

⇒10 sec=[tex]\frac{10}{60}[/tex] minute

So volume displace in liters/minute=31.8 liters/minute.

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