Answer:
96.1%
Explanation:
We know that lift force
[tex]F_L=\dfrac{1}{2}C_L\rho AV^2[/tex]
------------(1)
Where [tex]C_L[/tex] is the lift force coefficient .
ρ is the density of fluid.
A is the area.
V is the velocity.
Now when speed is increased by 2 % and all other parameter remains constant except [tex]C_L[/tex] .
Let;s take new value of lift force coefficient is [tex]C_L'[/tex] .
[tex]F_L=\dfrac{1}{2}C_L'\rho A(1.02V)^2[/tex]
-----------(2)
Now from equation 1 and 2
[tex]C_L\times V^2=C_L'\times1.0404 V^2[/tex]
⇒[tex]C_L'=0.961C_L[/tex]
So we can say that revised value of lift force coefficient is 96.1% of original value.