Answer:[tex]\frac{^{10}C_5}{^{12}C_5}[/tex]
Step-by-step explanation:
Given a total of 12 diesel engines
out of which 2 are defective
Company have to choose 5 good engines to ship.
Therefore no of ways in good engines are selected is [tex]^{10}C_5[/tex]
no of ways in which any 5 engines are selected from a total of 12 engines is
[tex]^{12}C_5[/tex]
Therefore the required probability =[tex]\frac{^{10}C_5}{^{12}C_5}[/tex]
=[tex]\frac{7}{22}[/tex]=0.318
