Question

When adjusted for any changes in ΔH and ΔS with temperature, the standard free energy change ΔG∘T at 2400 K is equal to 1.22×105J/mol . Calculate the equilibrium constant at 2400 K .

Answer 1

Answer:

K=0.0022

Explanation:

ΔG° = 1.22×10⁵ J/mol

Temperature (T) = 2400 K

ΔG° = - RT ln K

where R is gas constant whose value is 8.314 J/Kmol

           K  is equilibrium constant

           ΔG° standard free energy

ln K = $-\frac{\Delta G^o }{RT}$

K =  $e^{-\frac{\Delta G^o }{RT}}$

K = $e^{-\dfrac{1.22 \times 10^5 }{8.314 \times 2400}}$

K= 0.0022

hence equilibrium constant value is K=0.0022