Answer : The assumptions appears reasonable for the isothermal process is, [tex]\Delta U=0[/tex] and [tex]\Delta H=0[/tex]
Explanation :
First law of thermodynamic : It states that the energy can not be created or destroyed, it can only change or transfer from one state to another state.
As per first law of thermodynamic,
[tex]\Delta U=q+w[/tex]
The expression for internal energy is:
[tex]\Delta U=nC_vdt[/tex]
The expression for enthalpy is:
[tex]\Delta H=nC_pdt[/tex]
where,
[tex]\Delta U[/tex] = internal energy
q = heat
w = work done
n = number of moles
[tex]C_v[/tex] = specific heat capacity at constant volume
[tex]C_p[/tex] = specific heat capacity at constant pressure
[tex]dt[/tex] = change in temperature
As we know that, the term internal energy and enthalpy is the depend on the temperature and the process is isothermal that means at constant temperature.
T = constant
[tex]\dt[/tex] = 0
So, at constant temperature the internal energy and enthalpy is equal to zero. That means,
[tex]\Delta U=0[/tex] and [tex]\Delta H=0[/tex]